Let `f (x0 =x^(2) -2x -3, x ge 1 and g (x)=1 +sqrt(x+4), x ge-4` then the number of real solution os equation `f (x) =g (x)` is/are

Let f (x)=x^(2) -2x -3, x ge 1 and g (x)=1 +sqrt(x+4), x ge-4 then the number of real solution os equation f (x) =g (x) is/are

Let f:R rarr R,f(x)=ln(x+sqrt(x^(2)+1)) and g:R rarr R,g(x)={x^((1)/(3)),x 1 then the number of real solutions of the equation,f^(-1)(x)=g(x) is

Let f(x)=x^(2)- x+1, x ge 1//2 , then the solution of the equation f^(-1)(x)=f(x) is

Let f(x)=x^(2)-x+1, AA x ge (1)/(2) , then the solution of the equation f(x)=f^(-1)(x) is

Let f(x)=x^(2)-x+1, AA x ge (1)/(2) , then the solution of the equation f(x)=f^(-1)(x) is

Let f_(1) (x) and f_(2) (x) be twice differentiable functions where F(x)= f_(1) (x) + f_(2) (x) and G(x) = f_(1)(x) - f_(2)(x), AA x in R, f_(1) (0) = 2 and f_(2)(0)=1. "If" f'_(1)(x) = f_(2) (x) and f'_(2) (x) = f_(1) (x) , AA x in R then the number of solutions of the equation (F(x))^(2) =(9x^(4))/(G(x)) is...... .

Let f_(1) (x) and f_(2) (x) be twice differentiable functions where F(x)= f_(1) (x) + f_(2) (x) and G(x) = f_(1)(x) - f_(2)(x), AA x in R, f_(1) (0) = 2 and f_(2) (0) = 1. "If" f'_(1)(x) = f_(2) (x) and f'_(2) (x) = f_(1) (x) , AA x in R . then the number of solutions of the equation (F(x))^(2) =(9x^(4))/(G(x)) is...... .

Let f_(1) (x) and f_(2) (x) be twice differentiable functions where F(x)= f_(1) (x) + f_(2) (x) and G(x) = f_(1)(x) - f_(2)(x), AA x in R, f_(1) (0) = 2 and f_(2)(0)=1. "If" f'_(1)(x) = f_(2) (x) and f'_(2) (x) = f_(1) (x) , AA x in R then the number of solutions of the equation (F(x))^(2) =(9x^(4))/(G(x)) is...... .

The absolute valued function f is defined as f(x) = {{:(x,, x ge 0),(-x ,, x lt 0):}} and fractional part function g(x) as g(x) = x-[x], graphically the number of real solution(s) of the equation f(x) = g(x) is obtained by finding the point(s) of interaction of the graph of y = f(x) and y = g(x). The number of solution (s) |x-1| - |x+2| = k , when -3 lt k lt 3

The absolute valued function f is defined as f(x) = {{:(x,, x ge 0),(-x ,, x lt 0):}} and fractional part function g(x) as g(x) = x-[x], graphically the number of real solution(s) of the equation f(x) = g(x) is obtained by finding the point(s) of interaction of the graph of y = f(x) and y = g(x). The number of solution (s) |x-1| - |x+2| = k , when -3 lt k lt 3