Statement-1: In YDSE, if a thin film is indroduced in front of the upper slit then the fringe pattern shifts in the downward direction.
Statement-2: in YDSE if the slit widths are unequal the minima will be completely dark.

A thin glass plate is introduced in front of one of the double slits. What will happen to the fringe width?

A bright fringe is formed in front of one of the double slits. What will be the fringe width of the interference pattern?

In a regular YDSE, when thin film of refractive index mu is placed in front of the upper slit then it is observed that the intensity at the central point becomes half of the original intensity. It is also observed that the initial 3^(rd) maxima is now below the central point and the initial 4^(th) minima is above the central point. Now, a film of refractive index mu_(1) and thickness same as the above film. is put in the front of the lower slit also. It is observed that whole fringe pattern shifts by one fringe width. What is the value of mu_(1) ?

A thin transparent sheet is placed in front of a Young's double slit. The fringe width will

Assertion: White light is used in YDSE. Now, a glass slab is inserted in front of the slit S_1 . Then, red fringe will shift less (in upward direction) compared to violet. Reason: Refractive index for violet colour will be more.

Interference fringes were produced in Young's double-slit experiment using light of wavelength 5000 Å . When a film of thickness 2.5xx10^(-3) cm was placed in front of one of the slits, the fringe pattern shifted by a distance equal to 20 fringe-widths. The refractive index of the material of the film is

Interference fringes were produced in Young's double-slit experiment using light of wavelength 5000 Å . When a film of thickness 2.5xx10^(-3) cm was placed in front of one of the slits, the fringe pattern shifted by a distance equal to 20 fringe-widths. The refractive index of the material of the film is

In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .

In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .