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If the lines ax+by+c=0, bx+cy+a=0 and cx...

If the lines `ax+by+c=0, bx+cy+a=0 and cx+ay+b=0 (a, b,c` being distinct) are concurrent, then (A) `a+b+c=0` (B) `a+b+c=0` (C) `ab+bc+ca=1` (D) `ab+bc+ca=0`

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