Prove that the product of the perpendiculars from `(alpha,beta)` to the pair of lines `a x^2+2h x y+b y^2=0` is `(aalpha^2+2halphabeta+b beta^2)/(sqrt((a-b)^2+4h^2))`

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines a x^2+2h x y+b y^2=0 is (aalpha^2-2halphabeta+bbeta^2)/(sqrt((a-b)^2+4h^2))

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines a x^2+2h x y+b y^2=0 is (aalpha^2-2halphabeta+bbeta^2)/(sqrt((a-b)^2+4h^2))

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines ax^(2)+2hxy+by^(2)=0 is (a alpha^(2)-2h alpha beta+b beta^(2))/(sqrt((a-b)^(2)+4h^(2)))

Show that the product of perpendicular from (alpha, beta) to the pair of lines ax^2 + 2hxy + by^2= 0 is |(aalpha^2 + 2h alpha beta + b beta^2)/(sqrt((a-b)^2 - (2h)^2))|

Show that the product of the perpendicular from (alpha,beta) to the pair of lines S-= ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 is (|aalpha^(2)+2halphabeta+2galpha+2fbeta+c|)/(sqrt((a-b)^(2)+4h^(2))) Hence or otherwise find the product of the perpendicular from the origin

The product of the perpendiculars from origin to the pair of lines a x^2+2h x y+b y^2 + 2gx + 2fy + c =0 is

The product of the perpendiculars from origin to the pair of lines a x^2+2h x y+b y^2 + 2gx + 2fy + c =0 is

prove that the product of the perpendiculars drawn from the point (x_1, y_1) to the pair of straight lines ax^2+2hxy+by^2=0 is |(ax_1^2+2hx_1y_1+by_1^2)/sqrt((a-b)^2+4h^2)|