A black body is at a temperature of `527^(@)C`, to radiate twice as much energy per second its temperature must be increased to

A black body at a temperature of 227^(@)C radiates heat energy at the rate of 5 cal/cm-sec. At a temperature of 727^(@)C , the rate of heat radiated per unit area in cal/cm will be

A black body at a temperature of 127^(@)C raidates heat at the rate of 1cal//cm xx sec . At a temperature of 527^(@)C the rate of heat radiation from the body in (cal//cmxx sec) will be

A black body at a temperature of 227^(@)C radiates heat energy at the rate of 5 cal/ cm^(2) -sec. At a temperature of 727^(@)C , the rate of heat radiated per unit area in cal/ cm^(2) -sec will be

A black body at high temperature emits thermal radiations of

A black body A at a temperature of 527^(@)C , emits radiant energy at the rate of 16 watt. Another black body B at temperature 127^(@)C , emits radiant energy at the rate 8 watt in the same surrounding. Compare the surface areas of A and B.

The rectangular surface area 12cm xx 6cm of a black body at a temperature of 127^(@)C , emits heat energy at the rate of Q units per second. If the length and breadth of the surface area are each reduced to half of its initial value and the temperature is increased to 327^(@)C , then the rate of emission of heat energy will be

A black body at a temperature of 227 ^@C radiates heat at a rate of 5 cal//cm^2s . At a temperature of 727 ^@C , the rate of heat radiated per unit area will be

A perfectly black body emits radiation at temperature T_(1) K. If is to radiate at 16 times this power, its temperature T_(2) K should be

A black body radiates 3 joule per square centimeter per second when its temperature is 127^(@)C .How much heat will be radiated per square centimetre per second when its temperature is 527^(@)C ?

For a black body at temperature 527^(@)C , its radiating power is 60 W and temperature of surrounding is 127^(@)C . If the temperature of the black body iss changed to 927^(@)C , then its radiating power will be:-