When wave of wavelength `0.2cm`is made incident normally ona slit of width `0.004m`then the semui-angular width of central maximum of diffraction patten will be-

Light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. The angular width of central maxima in the diffraction pattern is

Light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. The angular width of central maxima in the diffraction pattern is

Angular width of central maximum in diffraction at a single slit is……………. .

Angular width of central maximum in diffraction at a single slit is……………. .

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Calculate the angular width of central maximum on a screen distance 9 m?

Light of wavelength 600nm is incident normally on a slit of width 0.2 mm. The anuglular width of central maxima in the diffraction pattern is (measured from miminum to minimum )

Plane wave of lamda=600 nm incident normally on a slit of width 0.18 mm. Calculate the total angular wideth of the central maximum.

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :