A vernier calipers has positive zero error of 0.05 mm. While finding the diameter a cyclinder, the MSR is 9 mm ad the VCD is 9. If the least count of the vernier calipers is 0.1 mm, the area of cross- section of the cylinder is ________ `mm^(2)`

(I) Least count of screw gauge is 0.01 mm (II) Least count of vernier calliper is 0.1mm Which one is correct?

While finding the internal diameter of a pipe using a vernier calipers, the M.S.R. = 18 mm, the vernier scale coinciding division is 3. If the least count of the instrument is 0.1 mm, then the internal radius is _________ mm.

Find the least count of the vernier caliper as shown in figure below. The main scale is in mm (i.e., 10mm, 20mm etc.)

A vernier caliper with a least count of of 0.01 cm was used to measure diameter of cylinder as 4 cm and a scale (0-15cm) with the least count of 1 mm was used to measue a length of 5cm . The % error in the measurement of volume of the cylinder is

A vernier caliper with a least count of of 0.01 cm was used to measure diameter of cylinder as 4 cm and a scale (0-15cm) with the least count of 1 mm was used to measue a length of 5cm . The % error in the measurement of volume of the cylinder is

The vernier constant of a vernier callipers is 0.1 mm and it has a positive zero error of 0.04 cm . While measuring diameter of a rod, the main scale reading is 1.2 cm and 5th vernier division is coinciding with any scale division. The correct diameter of the rod is

If in a Vernier callipers 10 VSD coincides with 8 MSD, then the least count of Vernier calliper is [given 1 MSD = 1mm]

If in a Vernier callipers 10 VSD coincides with 8 MSD, then the least count of Vernier calliper is [given 1 MSD = 1mm]

Two similar wires under the same load yield elongation of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm^(2) , then the area of cross-section of the second wire is

Two similar wires under the same load yield elongation of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm^(2) , then the area of cross-section of the second wire is