The force acting on the block of mass `1 kg` is given by `F=5-2t`. The frictional force acting on the block after time `t=2` seconds will be: `(mu=0.2)`

The force acting on the block is given by F = 5 - 2t . The frictional force acting on the block after time t = 2 seconds will be: ( mu = 0.2)

The frictional force acting on 1 kg block is

The frictional force acting on 1 kg block is

The friction force acting on the block at time t = 4 s will be

A block of mass 4kg is placed on a rough horizontal plane A time dependent horizontal force F =kt acts on the block (k =2N//s) . Find the frictional force between the block and the plane at t =2 seconds and t =5 seconds (mu =0.2) .

A block of mass 4 kg is placed on a rough horizontal plane. A time dependent horizontal force F = kt acts on the block (k = 2 N/s). Find the frictional force between the block and the plane at t = 2 second and t = 5 second (mu = 0.2)

A block of mass 4 kg is placed on a rough horizontal force plane. A time dependent horizontal force F = k t acts on the block. Here k = 2 Ns^(-1) . The frictional force between the block and plane at time t = 2 s is (mu = 0.2)