For the curve `x=t^(2)-1, y=t^(2)-t`, the tangent is parallel to X-axis at the point where

For the curve x = t^(2)-1, y = t^(2)-t the tangent line is perpendicular to x-axis when

For the curve x=t^(2)-1,y=t^(2)-t, the tangent line is perpendicular to x -axis,then t=(i)0(ii)prop(iii)(1)/(sqrt(3))(iv)-(1)/(sqrt(3))

For the curve x = t^2 - 1, y = t^2 - t, the tangent line is perpendicular to x -axis, then t = (i) 0 (ii) infty (iii) 1/(sqrt3) (iv) -1/(sqrt3)

If the tangent to the curve x = t^(2) - 1, y = t^(2) - t is parallel to x-axis , then

For the curve x = e^(t) cos t, y = e^(t) sin t the tangent line is parallel to x-axis when t is equal to

Find the point on the curve y^2-x^2 + 2x-1 = 0 where the tangent is parallel to the x-axis.