Let `f(x)={{:(x^(2)-ax+1",", x lt 0),(b(1-x)^(3)",", x ge0):}`. If is a differentiable function, then the ordered pair (a, b) is

If f(x)={{:(,ax^(2)-b,|x|lt 1),(,(1)/(|x|),|x| ge1):} is differentiable at x=1, then

If f(x)={{:(,ax^(2)-b,|x|lt 1),(,(1)/(|x|),|x| ge1):} is differentiable at x=1, then

If alpha and beta are such that the function f (x) defined by f (x) = {:{(alphax^(2) - beta",","for"|x|lt 1),((_1)/(|X|)",","for"|x|ge1):} is differentiable everywhere, then the ordered pair (alpha,beta) =

If f(x) = {{:( e^(x) +ax ,"for " x lt 0 ),( b(x-1) ^(2) ,"for " xge 0):}, is differentiable at x =0,then (a,b) is

If f(x) = {{:( e^(x) +ax ,"for " x lt 0 ),( b(x-1) ^(2) ,"for " xge 0):}, is differentiable at x =0,then (a,b) is