In a double experiment D=1m, d=0.2 cm and `lambda = 6000 Å`. The distance of the point from the central maximum where intensity is 75% of that at the centre will be:

In YDSE a = 2mm , D = 2m, lambda = 500 mm. Find distance of point on screen from central maxima where intensity becomes 50% of central maxima

In YDSE a = 2mm , D = 2m, lambda = 500 mm. Find distance of point on screen from central maxima where intensity becomes 50% of central maxima

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In an arrangement of double slit arrangement fig. The slits are illuminated by light of wavelenth 600 mm. The distance of the first point on the screen from the centre maximum where intensity is 75% of central maximum is

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.