If `y = mx + c` is a tangent to the circle `(x – 3)^2 + y^2 = 1` and also the perpendicular to the tangent to the circle `x^2 + y^2 = 1` at `(1/sqrt(2),1/sqrt(2))`, then

The equation to the tangent to the circle x^2+y^2+2x-1=0 at (-1,sqrt2) is

If a line, y = mx + c is a tangent to the circle, (x-1)^2 + y^2 =1 and it is perpendicular to a line L_1 , where L_1 is the tangent to the circle x^2 + y^2 = 8 at the point (2, 2), then :

If a line, y = mx + c is a tangent to the circle, (x-1)^2 + y^2 =1 and it is perpendicular to a line L_1 , where L_1 is the tangent to the circle x^2 + y^2 = 8 at the point (2, 2), then :

The equation to the tangent to the circle x^2+y^2-x+3y=10 at (-2,1) is

If y = 2sqrt2x+c is a tangent to the circle x^(2) +y^(2) = 16 , find the value of c.

If y=mx+c is a tangent to the circle x^2+y^2=1 , show that c=+-sqrt(1+m^2)

If y+c=0 is a tangent to the circle x^2+y^2-6x-2y+1=0 at (a,4) then

If the tangent from a point p to the circle x^2+y^2=1 is perpendicular to the tangent from p to the circle x^2 +y^2 = 3 , then the locus of p is