The `vec b` which is collinear with the vector `vec a = (2,1,-1)` and satisfies the relation `vec a. vecb =3` is

A vecotr vec(b) is collinear with the vector vec(a)= (2, 1, -1) and satisfies the condition vec(a). vec(b)= 3 . What is vec(b) equal to ?

If the vector vec b is collinear with the vector vec a(2sqrt(2),-1,4) and |vec b|=10, then

Find the vector a which is collinear with the vector vec b=2hat i-hat j and vec a*vec b=10

Vector vec x satisfying the relation vec A*vec x=c and vec B xxvec x=vec B is :

Three non-zero vectors vec(a), vec(b), vec(c) are such that no two of them are collinear. If the vector (vec(a)+vec(b)) is collinear with the vector vec(c) and the vector (vec(b)+vec(c)) is collinear with vector vec(a) , then prove that (vec(a)+vec(b)+vec(c)) is a null vector.

Given three vectors vec a,vec b, and vec c two of which are non-collinear.Further if (vec a+vec b) is collinear with vec c,(vec b+vec c) is collinear with vec a,|vec a|=|vec b|=|vec c|=sqrt(2). Find the value of vec a.vec b+vec b.vec c+vec c.vec a.3 b.-3 c.0 d.cannot be evaluated

Let vec a,vec b and vec c be three non-zero vectors, no two of which are collinear.If the vector 3vec a+7vec b is collinear with vec c and 3vec b+2vec c is collinear with bar(a), then 9vec a+21vec b+14vec c is equal to.

vec a,vec b and vec c are three non-zero vectors,no two of which are collinear and the vectors vec a+vec b is collinear with vec b,vec b+vec c is collinear with vec a, then vec a+vec b+vec c=

Given three vectors vec a , vec b ,a n d vec c two of which are non-collinear. Further if ( vec a+ vec b) is collinear with vec c ,( vec b+ vec c) is collinear with vec a ,| vec a|=| vec b|=| vec c|=sqrt(2)dot Find the value of vec a. vec b+ vec b. vec c+ vec c. vec a a. 3 b. -3 c. 0 d. cannot be evaluated

Given three vectors vec a , vec b ,a n d vec c two of which are non-collinear. Further if ( vec a+ vec b) is collinear with vec c ,( vec b+ vec c) is collinear with vec a ,| vec a|=| vec b|=| vec c|=sqrt(2)dot Find the value of vec a. vec b+ vec b. vec c+ vec c. vec a a. 3 b. -3 c. 0 d. cannot be evaluated