A cylindrical rod having temperature `T_(1)` and `T_(2)` at its ends. The rate of flow of heat is `Q_(1) cal//sec`. If all the linear dimensions are doubled keeping temperature constant, then rate of flow of heat `Q_(2)` will be

A cylindrical rod having temperature T_1 , and T_2 at its ends. The rate of flow of heat is Q_1 (cal)/s . If all the linear dimensions are doubled keeping temperature constant then rate of flow of heat Q_2 , will be

A cylinderical rod has temperature T_(1) and T_(2) at its ends. The rate of flow of heat is Q^(1) cal/s. if all the linear dimensions are doubled keeping temperature constant then rate of flow of heat Q_(2) will be

A cylindrical rod having temperature T_(1) and T_(2) at its end. The rate of flow of heat is Q_(1)("Cal")/(s) If all linear dimensions are doubled keeping temperature constant, then the rate of flow of heat Q_(2) in ("Cal")/(s) will be . . . . . . . .

In Q.No.4-49, the lowest rate of flow of heat is for:

Rate of heat flow through a cylindrical rod is H_(1) . Temperatures of ends of rod are T_(1) and T_(2) . If all the dimensions of rod become double and temperature difference remains same and rate of heat flow becomes H_(2) . Then (H_(1))/(H_(2)) is 0.x . Find value of x.

Rate of heat flow through a cylindrical rod is H_(1) . Temperatures of ends of rod are T_(1) and T_(2) . If all the dimensions of rod become double and temperature difference remains same and rate of heat flow becomes H_(2) . Then (H_(1))/(H_(2)) is 0.x . Find value of x.