A body of mass 10 kg is acted upon by a force given by equation ` F=(3t^(2)-30)` Newtons. The initial velocity of the body is 10 m/s. The velocity of the body after 5 secs. is

A body of mass 10 kg is upon by a force given by equation F=(3t^(2)-30) newtons. The initial velocity of the body is 10 m/s. The velocity of the body after 5 sec. is

A body of mass 10 kg is upon by a force given by equation F=(3t^(2)-30) newtons. The initial velocity of the body is 10 m/s. The velocity of the body after 5 sec. is

A body of mass 10 kg is being acted upon by a force 3t^2 and an opposing constant force of 32 N. The initial speed is 10 ms^-1. The velocity of body after 5 s is

A body of mass 10 kg is being acted upon by a force 3t^2 and an opposing constant force of 32 N. The initial speed is 10 ms^-1. The velocity of body after 5 s is

A body of mass 3 kg at rest is acted upon by a force and the body moves through a distance 20 m in 5 s. Force on the body is

Solve the following examples: (numerical problems) A body of mass 1 kg, moving with a velocity of 4 m/s collides with a body of mass 0.5 kg moving with a velocity of 2 m/s . If the velocity of the first body after collision is 8/3 m/s , find the velocity of the second body after collision.

A body of mass 2 kg collides with a body of mass 1 kg. Their initial velocities are 6 m/s and 4 m/s respectively. If the velocity of the first body after collision is : (14)/3 m/s , find the velocity of the second body after collision.

A body of mass 5 kg is raised vertically to a height of 10 m by a force 170 N. The velocity of the body at this height will be

A body of mass 5 kg is raised vertically to a height of 10 m by a force 170 N. The velocity of the body at this height will be