A particle is projected with velocity `v_(0)` along x - axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e. `a=-x^(2)`. The distance at which particle stops is -

A particle is projected with velocity V_(0) along axis x . The deceleration on the particle is proportional to the square of the distance from the origin i.e., a=omegax^(2). distance at which the particle stops is

A particle of mass m is projected upword with velocity v=(v_(e))/(2) ( v_(e)) escape of the particle is

The distance travelled by a particle is proportional to the squares of time, then the particle travels with

The distance travelled by a particle is proportional to the squares of time, then the particle travels with

A particle moves along the X-axis with velocity v = (dx)/(dt)=f(x) then the acceleration of the particle is

A particle is projected on x axis with velocity V. A force is acting on it in opposite direction, which is proportional to square of its position. At what distance from origin the particle will stop (m is mass, k = proportionality constant)

A particle starts with speed v_(0) from x = 0 along x - axis with retardation proportional to the square of its displacement. Work done by the force acting on the particle is proportional to

A particle starts with speed v_(0) from x = 0 along x - axis with retardation proportional to the square of its displacement. Work done by the force acting on the particle is proportional to