Find the ratio of magnetic dipole moment and magnetic field at the centre of a disc. Radius of disc is `R` and it is rotating at constant angular speed o about its axis. The disc is insulating and uniformly charged

Moment of inertia of a disc about an axis parallel to diameter and at a distance x from the centre of the disc is same as the moment of inertia of the disc about its centre axis. The radius of disc is R . The value of x is

Moment of inertia of a disc about an axis parallel to diameter and at a distance x from the centre of the disc is same as the moment of inertia of the disc about its centre axis. The radius of disc is R . The value of x is

A disc of the moment of inertia 'l_(1)' is rotating in horizontal plane about an axis passing through a centre and perpendicular to its plane with constant angular speed 'omega_(1)' . Another disc of moment of inertia 'I_(2)' . having zero angular speed is placed discs are rotating disc. Now, both the discs are rotating with constant angular speed 'omega_(2)' . The energy lost by the initial rotating disc is

A disc of the moment of inertia 'l_(1)' is rotating in horizontal plane about an axis passing through a centre and perpendicular to its plane with constant angular speed 'omega_(1)' . Another disc of moment of inertia 'I_(2)' . having zero angular speed is placed discs are rotating disc. Now, both the discs are rotating with constant angular speed 'omega_(2)' . The energy lost by the initial rotating disc is

A disc of moment of inertia la is rotating in a horizontal plane about its symmetry axis with constant angular speed co. Another discinitially at rest of moment of inertia I, is dropped coaxially on to the rotating disc. Then, both the discs rotate with same constant angular speed The loss of kinetic energy due to friction in this process is,