The hybrid states of carbon atoms in `overset(B)((CN)_(4))overset(A)(C_(2))` are A and B and number of `pi` bonds in compounds is C. Then:

Hybridization of 1 and 2 carbon atoms in overset(1)(CH_(2))=overset(2)(C)=CH_(2)

What is the hybrid state of each carbon overset**CH_2=overset**C=overset**CH_2

The carbon atoms in the compound (CN)_(4)C_(2) are

The hybridization of the negetively charged C atom of overset(-)overset(..)CH_(3) , is

Carbon has the unique property to form bonds with other atoms of carbon. -overset(|)(C)-overset(|)underset(-overset(|)underset(|)(C)-)(C)-overset(|)(C)- Carbon forms large number of compounds due to:

The hybridization states of carbon atom (1) and carbon atom (2) in the compound N-=overset(1)(C )-overset(2)(CH) =overset(3)(CH_(2)) are, respectively,

The bond between carbon atoms 1 and 2 in the compound : N-=overset(1)(C)-overset(2)(C)H=CH_(2) involves the hybridised carbon as :