A particle is executing SHM with time period T Starting from mean position, time taken by it to complete `(5)/(8)` oscillations is,

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle executing SHM with time period T and amplitude A. The mean velocity of the particle averaged over quarter oscillation, is

A particle executing SHM with time period T and amplitude A. The mean velocity of the particle averaged over quarter oscillation, is

A particle executes SHM with a time period of 8 s. It is starts from the extreme position at time t = 0, the ratio of distances covered by it in 1st and 2nd seconds is

A particle executes SHM with a time period of 8 s . If it starts from the extreme position at time t = 0 , the ratio of distance covered by it in 1st and 2nd seconds is

A particle executing SHM with time period of 2 s : Find the time taken by it to move from one amplitude to half the amplitude position.

A particle is executing SHM on x-axis starting from mean position. At time t and 2t respectively, position of the particle along x-axis are at x = M and x = N then Show time period, T=(2pit)/(cos^(-1)(N/(2M)))

A particle executes SHM with a time period of 4 s . Find the time taken by the particle to go from its mean position to half of its amplitude . Assume motion of particle to start from mean position.