In the balanced equation
`MnO_(4)^(-)+H^(+)+C_(2)O_(4)^(2-)rarr Mn^(2+)+CO_(2)+H_(2)O`, the moles of `CO_(2)` formed are :-

For the redox reaction MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O The correct coefficients of the reactants for the balanced reaction are

For the redox reaction, MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O the correct coefficients of the reactants for the balanced reaction are

KMnO_(4) react with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O , here 20 ml of 0.1 M KMnO_(4) is equivalemt to

In the reaction C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O the reductant is

For the redox reaction x MnO_(4)^(-) + yH_(2)C_(2)O_(4) + zH^(+) to m Mn^(2+) +n CO_(2) + p H_(2)O The valeu of x, y, m and n are