In the Wheatstone's bridge shown, `P = 2 Omega, Q = 3 Omega, R = 6 Omega` and `S = 8 Omega`. In order to obtain balance, shunt resistance across S must be

In a Wheatstone bridge circuit, P=5 Omega, Q=6 Omega, R=10 Omega and S= 5 Omega . Find the additional resistance to be used in series with S, so that the bridge is balanced.

In Wheatstone's network P = 2 Omega , Q = 2 Omega , R = 2 Omega and S = 3 Omega The resistance with which S is to shunted in order that the bridge may be balanced is

In the Wheatstone’s network given below , P = 10 Omega, Q = 20 Omega, R = 15 Omega, S = 30 Omega . The current passing through the battery (of negligible internal resistance) is

In the Wheatstone bridge network ABCD is balanced when P = 500 Omega, Q = 250 Omega and S = 12 Omega , what is the value of R ?

In the Wheatstone's network given, P = 10 Omega, Q = 20 Omega, R = 15 Omega, S = 30 Omega .The current passing through the battery (of negligible internal resistance) is

In Wheatstone bridge, the resistances in four arms are 10Omega,10Omega,10Omega and 20Omega . To make the bridge balance, resistance connected across 20Omega is

In Wheatstone network, P=2Omega , Q=2 Omega , R=2Omega and S = 3 Omega . The resistance with which is to be shunted in order that the bridge may be balanced is: