The radius of curvature of each surface of a biconcave lens made up of glass of refrative indx `1.5` is 30 cm. the focal length of the lens is

The radius of curvature of each face of a biconcave lens made of glass of refractive index 1.5 is 30 cm. Calculate the focal length of the lens is air.

The radius of curvature of each face of biconcave lens, made of glass of refractive index 1.5 is 30 cm. Calculate the focal length of the lens in air.

In figure, an air lens of radius of curvature of each surface equal to 10 cm is cut into a cylinder of glass of refractive index 1.5. The focal length and the nature of lens are

In figure, an air lens of radius of curvature of each surface equal to 10 cm is cut into a cylinder of glass of refractive index 1.5. The focal length and the nature of lens are

If radius of curvature of curved surface of plano-convex lens of refractive index 1.5 is 60 cm, then its focal length is ...... cm.

The radii of curvatures of both surfaces of a double convex lens made of glass, (mu = 1.5) is R. Its focal length is

The effective focal length of the lens combination shown in figure is -60 cm. The radius of curvature of the curved surfaces of the plano-convex lenses are 12 cm each and refractive index of the material of the lens is 1.5. The refractive index of the liquid is

The radius of curvature of curved surface of a thin plano-convex lens is 10 cm and the refractive index is 1.5 . If the plano surface is silvered, then the focal length will be.