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Addition of 0.643g of a compound to 50mL...

Addition of `0.643g` of a compound to `50mL` of benzene (density: `0.879g mL^(-1))`lower the freezing point from `5.51^(@)C` to `5.03^(@)C`. If `K_(f)` for benzene is `5.12 K kg mol^(-1)`, calculate the molar mass of the compound.

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Addition of 0.40 g of a compound to 45.5 m L of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51^(@)C to 4.998^(@)C .If K_(f) for benzene is 5.12 K kg mol^(-1) ,calculate the molar mass of the compound.

Addition of 0.40 g of a compound to 45.5 m L of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51^(@)C to 4.998^(@)C .If K_(f) for benzene is 5.12 K kg mol^(-1) ,calculate the molar mass of the compound.

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The addition of 0.643 g of a compound to 50 mL of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51 to 5.03^(@)C . If K_(f) for benzene is 5.12 , calculate the molecular weight of the compound.

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