A simple pendulum has time period (T_1). The point of suspension is now moved upward according to the relation `y = K t^2, (K = 1 m//s^2)` where (y) is the vertical displacement. The time period now becomes (T_2). The ratio of `(T_1^2)/(T_2^2)` is `(g = 10 m//s^2)`.

A simple pendulum has time period T_(1) The point of suspension is now moved upward according to the relation y = kt^(2)(k = 1 m//s^(2)) where y is vertical displacement, the time period now becomes T_(2) . The ratio of ((T_(1))/(T_(2)))^(2) is : (g = 10 m//s^(2))

A simple pendulum has time period T_1 . The point of suspension is now moved upward according to the relation. y = kt^2 (k = 2 m/ s^2 ) where y is the vertical displacement. The time period now becomes T_2 then the ratio of T_1^2 / T_2^2 (g = 10 m/ s^2 )

A simple pendulum has time period T_(1) / The point of suspension is now moved upward according to the realtion y = kt^(2)(k = 1 m//s^(2)) where y is vertical displacement, the time period now becomes T_(2) . The ratio of ((T_(1))/(T_(2)))^(2) is : (g = 10 m//s^(2))

A simple pendulum has time period T_1. The point of suspension is now moved upward according to the relatiori. y = kt^2 (k = 2 m/ s^2 ) where y is the vertical displacement. The time period now becomes T_2 then the ratio of T_1^2 / T_2^2 (g = 10 m/ s^2 )

A simple pendulum has time period T_(1) . The point of suspension is now moved upward according to the relation y= kt^(2)(k=1 ms^(-2)) where y is the vertical diplacement. The time period now becomes T_(2) . What is the ration (T_(1)^(2))/(T_(2)^(2)) ? Given g=10 ms^(-2)