Let the function f be defined by `f(x)={(3x0lexle1),(-3x+51ltxle2):}`, then:

Let the function f be defined f(x)={:{(3x,0lexle1),(-3x+5,1ltxle2):} then............

Let the function be defined as f(x)={4x 0ltxle1 (-4x+5) 1ltxlt2 then lim_(xrarr1)f(x) is :

Let the function f be defined by f(x)=((2x+1)/(1-3x)) then f^(-1)(x) is

Let f(x)={{:(3^x","-1lexle1),(4-x","1ltxle4):} then

Let f(x)={{:(3^x","-1lexle1),(4-x","1ltxle4):} then

Let f(x)={(x+1, -1lexle0),(-x,0ltxle1):} then

Let f(x)={(x+1, -1lexle0),(-x,0ltxle1):} then

The relation 'f' is defined by f(x)={(x^2,0lexle3), (3x, 3lexle10):} The relation 'g' is defined by g(x)= {(x^2,0lexle2), (3x, 2lexle10):} Show that 'f' is a function and 'g' is not a function.