Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Eletrons with de- Broglie wavwlength lambda fall on the target in an X- rays tube . The cut off wavelength of the emitted X- rays is

Electrons with de - Brogli wavelengtyh lambda fall on the target in an X-ray tube.The cut off wavelength of the emitted Xrays is (a) lambda_0 = (2mclambda^2)/(h) (b) lambda_0 = (2h)/(mc) (c ) lambda_0 (2m^2 c^2 lambda^3)/(h^2) (d) lambda_0 = lambda

Electrons with de - Brogli wavelengtyh lambda fall on the target in an X-ray tube.The cut off wavelength of the emitted Xrays is (a) lambda_0 = (2mclambda^2)/(h) (b) lambda_0 = (2h)/(mc) (c ) lambda_0 (2m^2 c^2 lambda^3)/(h^2) (d) lambda_0 = lambda

Electrons of mass m with de - Broglie wavelength , lambda fall on the target in an X-ray tube . The cutoff wavelength (lambda_0) of the emitted X-ray is:

The cut-off wavelength of an X-ray depends on