For the transistor circuit shown below, if `beta=100`, voltage drop between emitter and base is `0.7V` then value of `V_(CE)` will be

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and beta is 50, the base current if R_C is 2 kOmega is

A transistor connected in common emitter mode, the voltage drop across the collector is 2 V and beta is 50, the base current if R_C is 2 kOmega is

For a transistor in common emitter configuration, the voltage drop across the load of 1000 Omega is 0.5 V. If the value of alpha for the transistor is 0. 98, then the base current will be approximately equal to

Refer to the common emitter amplifier circuit shown below, using a transistor with beta =80 and V_(BE) = 0.7 volt. The value of resistance R_B is

For a transistor connected in common emitter mode, the voltage drop across the collector is 2V and beta is 50. Find the base current is R_(C) is 2K

In the circuit shown in figure, when the input voltage of the base resistance is 10 V, V_(be) is zero and V_(ce) is also zero. Then

In the circuit shown in figure, when the input voltage of the base resistance is 10 V, V_(be) is zero and V_(ce) is also zero. Then

For a transistor connected in common emitter mode , the voltage drop across the collector is 2 V and beta is 50 . Find base current if R_(C) is 2K .