A rectangular loop of dimensions `(axxb)` carries a current i. A uniform magnetic field `vec(B)=B_(0) hat(i)` exists in space. Then :

A rectangular loop of sides 20 cm and 10 cm carries a current of 5.0 A . A uniform magnetic field of magnitude 2 T exists parallel to the longer side of the loop. The torque acting on the loop is

A conducting circular loop of radiius r carries a constant current i . It is placed in a uniform magnetic field vec(B)_(0) such that vec(B)_(0) is perpendicular to the plane of the loop . The magnetic force acting on the loop is

A conducting circular loop of radiius r carries a constant current i . It is placed in a uniform magnetic field vec(B)_(0) such that vec(B)_(0) is perpendicular to the plane of the loop . The magnetic force acting on the loop is

A rectangular loop of size lxxb carrying a steady current I is placed in a uniform magnetic field vec(B) . Prove that the torque vec(tau) acting on the loop is given by vec(tau)=vec(m)xxvec(B) , "when " vec(m) is the magnetic moment of the loop .

A conducting circular loop of radius r carries a constant current I. It is placed in a uniform magnetic field vec(B) such that vec(B) is perpendicular to the plane of the loop. The magnetic force acting on the loop is

Figure shows a conducting Rectangular loop of electrical resistance R. There exists a uniform magnetic field given by vecB=B_(0)(10t^(2)-5t)hat(k) in the region. The current in the loop at

A rectangular loop of area A and carrying a steady current I is placed in a uniform magnetic field:-Derive the expression of torque, tau = barmxxbarB acting on the loop.