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The vapour pressure of pure liquids A an...

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase.
Apply Raoult's law `P_(T)=P_(A)^(0)x_(A)+P_(B)^(0)x_(B)=P_(B)^(0)x_(A)+P_(B)^(0)(1-x_(A))` to calculate mole fraction of `A(x_(A))` and `B(x_(B))`.
In vapour phase, partial pressure are used insted of number of moles.

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