If `sec theta - tan theta =(a+1)/(a-1),` then `cos theta =`

( sec theta + tan theta -1)/( tan theta - sec theta +1)

Prove that: (sec theta + tan theta -1)/(tan theta - sec theta +1) = (cos theta)/(1- sin theta)

Prove: sec theta + tan theta = 1/(sec theta - tan theta)

(1+sec theta - tan theta)/(1+sec theta + tan theta)=

Prove that: 1/(sec theta - tan theta) = sec theta + tan theta .

Prove that (1)/((sec theta - tan theta))-(1)/(cos theta)=(1)/(cos theta)-(1)/((sec theta+ tan theta)).

Prove that : sec theta + tan theta = (cos theta)/(1 - sintheta) = (1+ sin theta)/(cos theta)

Prove that (sec theta+tan theta -1)/(tan theta -sec theta +1)=cos theta/(1-sin theta)

((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) is equal to: ((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) बराबर है :

Prove the following identity : 1/(sec theta-tan theta)= (1+sin theta)/(cos theta) = sec theta+tan theta .