If `f:R rarr R` and `g:R rarr R` are define by `f(x)=3x-4` and `g(x)=2+3x`, then `(g^(-1)of^(-1))(5)=`

If f:R rarr and g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x then (g^(-1)" of"^(-1))(5)=

If f:R rarr R,g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x ,then (g^(-1) of^(-1))(5)=

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

If f:R rarr R, S: R rarr R are defined by f(x) = 3x-4, g(x) = 5x-1 then, (fog^(-1))(2) =

If f:R rarr R, g:R rarr R are defined by f(x)=x^(2)+2x-3, g(x)=3x-4 , then (fog)(-1)=

If f:R rarr R, g:R rarr R are defined by f(x)= 5x-3,g(x)=x^(2)+3 , then (gof^(-1))(3)=

If f:R rarr R and g:R rarr R given by f(x)=x-5 and g(x)=x^(2)-1, Find fog

If f:R rarr R, g:R rarr R are defined by f(x)=4x-1, g(x)=x^(3)+2, then (gof)((a+1)/(4))=

If f:R rarr R and g : R rarr R are defined by f(x) = 3x + 2 and g(x) = x^2 - 3 , then the value of x such that g(f(x))=4 are