AB is a chord of the parabola `y^2 = 4ax` with its vertex at A. BC is drawn perpendicular to AB meeting the axis at C.The projecton of BC on the axis of the parabola is

AB is the chord on the parabola y^(2)=4ax with its vertex at A.BC is drawn perpendicular to AB meeitng the axis at C. The projection of BC on the axis of the parabola is :

A B is a chord of the parabola y^2=4a x with vertex AdotB C is drawn perpendicular to A B meeting the axis at Cdot The projection of B C on the axis of the parabola is a (b) 2a (c) 4a (d) 8a

AB is a chord of a parabola y^(2)=4ax with the end A at the vertex of the given parabola BC is drawn perpendicular to AB meeting the axis of the parabola at C then the projection of BC on this axis is

PQ is a normal chord of the parabola y^2 =4ax at P, A being the vertex of the parabola. Through P, a line is drawn parallel to AQ meeting the x-axis at R. Then the line length of AR is

The vertex A of the parabola y^(2)=4ax is joined to any point P on it and PQ is drawn at right angles to AP to meet the axis in Q. Projection of PQ on the axis is equal to

If AB is a focal chord of the parabola y^(2)=4ax whose vertex is 0, then(slope of OA ) x (slope of OB)-

From the point where any normal to the parabola y^2 = 4ax meets the axis, is drawn a line perpendicular to this normal, prove that this normal always touches an equal parabola y^2 +4a(x-2a)=0 .