The parametric equations of the parabola `y^(2) = 12x ` are _

The parametric equations of the parabola y^(2) - 8x - 4y - 12 = 0 are

The parametric equation of the parabola are x=t^(2)+1,y=2t+1 The cartesian equation of the directrix is

Find the parametric equation of the parabola (x-1)^(2)=-16(y-2)

The parametric equation of a parabola is x=t^2+1, y=2t+1 . The cartesian equation of its directrix is

The parametric equations of a parabola are x=t^(2)+1,y=2t+1. The Cartesian equation of its directrix is x=0 b.x+1=0 c.y=0 d.none of these

The parametric equation of a parabola is x=t^(2)+1,y=2t+1. Then find the equation of the directrix.

The parametric equations of a parabola are x=t^2+1, y=2t+1. The Cartesian equation of its directrix is a. x=0 b. x+1=0 c. y=0 d. none of these