If the nitrogen atom has electronic configuration `1s^(7)`, it would have energy lower than that of the normal ground state configuration `1s^(2)2s^(2)2p^(3)` because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observed because it violates

If the Nitrogen atom had electronic configura - tion 1s^(7) , it would have energy lower than that of the normal ground state configuration 1s^(2)2s^(2)2p^(3) , because the electrons would be closer to the nucleus. Yet, 1s^(7) is not observed because it violates

If nitrogen atoms had electronic configuration 1s^(7) It would have energy lower than that of the normal ground state configuration 1s^(2) 2s^(2) 2p^(3) because the electrons would be closer to the nucleus yet 1s^(7) is not observed because it violates ?

If the electronic configuration of nitrogen had 1s^(7) , it would have energy lower than that of the normal ground 'state configuration 1s^(2)2s^(2)2p^(3) because the electrons would be closer to the nucleus. Yet 1s^(7) is not observe because it violates:

If the nitrogen atom had electronic configuration 1s^(7) is would have energy lower than that of the normal ground state configuration 1s^(2)2s^(2)2p^(3) because the electrons would be closer to the nucleus. Yet is not observed. It violates

If the nitrogen atom had electronic configuration '1 s^7', it would have energy lower than that of the normal ground state configuration '1 s^2 2 s^2 sp^3', because the elec- trons would be closer to the nucleus. Yet, '1 s^7' is not observed because it violates: