A body of mass 2 kg is moving with a velocity `8m//s` on a smooth surface. If it is to be brought to rest in 4 seconds, then the force to be applied is

A body of mass 2 kg is moving with a velocity of 8 m//s on a smooth surface. If it is to be brought to rest in 4 sec then force to be applied is--------.

A body of mass 2 kg is moving with a velocity of 8 m/s on a smooth surface. If it is to be brought to rest in 4 s,t hen force to be applied is

A body of mass 2 kg is moving with a velocity 8 m/s on a smooth surface. If it is to be brought to rest in 4 seconds, then the magnitude of force (in newton) to be applied in opposite direction of motion is

A body of mass 10 kg is moving with a velocity of 100 m/s. find the force needed to stop it in 5 seconds.

A motor car of mass 200 kg is moving with a velocity of 72 km/hr. By the application of brakes it is brought to rest in a distance of 100m. What is the force applied ?

A body of mass 2kg moving with a velocity of 10m//s is brought to rest in 5 sec . Calculate the stopping force applied.

A block of mass 0.50kg is moving with a speed of 2.00m//s on a smooth surface. It strikes another mass of 1 kg at rest and they move as a single body. The energy loss during the collision is

A block of mass 0.50kg is moving with a speed of 2.00m//s on a smooth surface. It strikes another mass of 1 kg at rest and they move as a single body. The energy loss during the collision is

A block of mass 0.50kg is moving with a speed of 2.00m//s on a smooth surface. It strikes another mass of 1 kg at rest and they move as a single body. The energy loss during the collision is