Home
Class 12
PHYSICS
An ideal inductive coil has a resistance...

An ideal inductive coil has a resistance of `100gamma` When an ac signal of frequency `100Hz` is applied to the coil the voltage leads the current by `45^(@)` The inductance of the coil is .

Promotional Banner

Similar Questions

Explore conceptually related problems

An ideal inductive coil has a resistance of 100Omega When an ac signal of frequency 1000Hz is applied to the coil the voltage leads the current by 45^(@) The inductance of the coil is .

An inductive coil has a resistance of 100 Omega . When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by 45^(@) . What is the inductance of the coil?

An inductive coil has a reactance of 100 Omega . When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by 45^(@) . What is the inductance of the coil?

An inductance coil has a reactance of 100Omega.When an ACsignal of frequency 1000Hz is applied to the coil the applied voltage leads the current by "45^(@The self-inductance of the coil is: (A) "6.7times10^(-7)H],[" (В) "5.5times10^(-5)H],[" (C) "1.1times10^(-1)H],[" (D) "1.1times10^(-2)H]]

An inductive coil has resisatance of 100 Omega . When an ac sinal of frequency 1000 Hz is fed to the coil. The applied voltage leads the current by 45^(@) . What is the inductance of the coil?

" A coil has an impedance of "10Omega" ,when an AC signal of frequency "(100)/(pi)Hz" ,is applied to the coil.The voltage leads the current by "45^(@)" ,the inductance of coil is "

A coil has an impedance of 10Omega ,when an ACsignal of frequency (100)/(pi)Hz ,is applied to the coil The voltage leads the current by 45 degree ,the inductance of coil is

An inductance coil has a impedance of 100 ohm. When a.c. signal of frequency 1,000 hz is applied to the coil, the applied voltage leads the current by 45^@ . Calculate the self inductance of the coil.

When an ac signal of frequency 1200 Hz is applied to a coil of reactance 120Omega , the applied voltage leads the current by 45^@ .Calculate the self inductance of the coil.