Let ABC be a triangle such that the coordinates of the vertex A are (3, 1). Equation of the median through B is `2x + y-3 = 0` and equation of the angular bisector of C is `7x-4y-1=0`. Find the slope of line BC.

Let ABC be a triangle such that the coordinates of A are (–3, 1). Equation of the median through B is 2x + y – 3 = 0 and equation of the angular bisector of C is 7x – 4y – 1 = 0. Then match the entries of column-I with their corresponding correct entries of column-II

In a triangle ABC, coordinates of A are (1,2) and the equations of the medians through B and C are x+y=5 and x=4 respectively. Find the coordinates of B and C.

Let in DeltaABC coordinates of vertex A is (0,0). Equation of the internal angle bisector of /_ABC is x + y - 1 = 0 and mid-point of BC is (1,3). The ordinate of vertex C is

In triangle ABC, the coordinates of the vertex A are , (4,-1) and lines x - y - 1 = 0 and 2x - y = 3 are the internal bisectors of angles B and C . Then the radius of the circles of triangle AbC is

In triangle ABC, the coordinates of the vertex A are , (4,-1) and lines x - y - 1 = 0 and 2x - y = 3 are the internal bisectors of angles B and C . Then the radius of the circles of triangle AbC is

In triangle ABC, the coordinates of the vertex A are , (4,-1) and lines x - y - 1 = 0 and 2x - y = 3 are the internal bisectors of angles B and C . Then the radius of the circles of triangle AbC is

In a triangle ABC, coordinate of A are (1,2) and the equations of the medians through B and C are respectively, x+y=5&x=4 . Then area of DeltaABC (in sq. units) is:

In /_ABC, vertex A is (1,2). If the internal angle bisector of /_B is 2x-y+10=0 and the perpendicular bisector of AC is y=x ,then find the equation of BC

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angular bisector of angleABC is x+y -2=0 Coordinates of vertex B