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If cos(alpha+beta)=4/5; sin(alpha-beta)=...

If `cos(alpha+beta)=4/5; sin(alpha-beta)=5/13` and `alpha,beta` lie between `0&pi/4` then find the value of `tan2alpha`

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`Cos(alpha+beta)=4/5` `Sin(alpha-beta)=5/13` `Sin(alpha+beta)=3/5` `alpha-beta=sin^-1(5/13)` `alpha+beta= sin^-1(3/5)` `2alpha=sin^-1(5/13)+sin^-1(3/5)` `sin(2alpha)=56/65`
`tan(2alpha)=56/33`
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