A solution of 0.4 g sample of `H_(2)O_(2)` reacted with 0.632 g of `KMnO_(4)` in presence of sulphuric acid. The percentage purity of the sample of `H_(2)O_(2)` is :

0.2 g if a sample of H_2 O_2 required 10 ml of 1 N KMnO_4 for titration in acidic medium. The percentage purity of H_2 O_2 sample is:

0.2 g if a sample of H_2 O_2 required 10 ml of 1 N KMnO_4 for titration in acidic medium. The percentage purity of H_2 O_2 sample is:

A 20 ml solution containing 0.2 g impure H_(2)O_(2) reacts completely with 0.316 g of KMnO_(4) in acidic medium. What would be volume strength of H_(2)O_(2) solution? [Given: Molar mass of H_(2)O_(2)=34 & KMnO_(4)= 158 g/mol]

20 mL of a solution containing 0.2g of impure sample of H_(2)O_(2) reacts with 0.316 g of KMnO_(4) (acidic). Calculate: (a) Purity of H_(2)O_(2) , (b) Volume of dry O_(2) evolved at 27^(@)C and 750 mm P .

20mL of H_(2)O_(2) solution is reacted with 80 mL of 0.05 M KMnO_(4) "in acidic medium then what is the volume strength of" H_(2)O_(2) ?

A 20.0 mL solution containing 0.2 impure H_2O_2 reacts completely with 0.316 g of KMnO_4 in acid solution . The purity of H_2O_2 (in%) is ...........(mol .wt.of H_2O_2=34 , mol . Wt . Of KMnO_4 = 158 )