The ion having comparable size with `O^(2-)` is:

The trivalent ion having size in lanthanide series is

Assertion: The ionic size of O^(2-) is bigger than that of F^(-) ions. Reason: O^(2-) and F^(-) are isoelectronic ions.

Assertion: The ionic size of O^(2-) is bigger than that of F^(-) ion. Reason: The O^(2-) and F^(-) are isoelectronic ions.

Why does O_(2)^(2-) possess a larger bond length as compared to O_(2)^(-) ion and O_2 molecule?

The Li^(+) ion, though smallest in size is the poorest conductor of electricity as compared to other alkali metal ions in water. This is due to :

The formation of the oxide ion O^(2-) (g) requires first an exothermic and then an endothermic step as shown below, O(g)+ e^(-) = O^(-)(g), DeltaH^(@)= -142kJmol^(-1) O^(-)(g) +e^(-) =O^(2-)(g), DeltaH^(@)= 844 kJmol^(-1) This is because : oxygen is more electronegative, oxygen has high electron affinity, O^(-) ion will tend to resist the addition of another electron , O^(-) ion has comparatively larger size than oxygen atom

If four elements with atomic numbers Z-2, Z-1, Z and Z + 1 are forming isoelectronic ions, the atomic number of the ion having largest size is

Compared to a human, a diving mammal of equal size has :

Lanthanoid contraction will not have any influence when we compare size of :-