The velocity ofacar travelling on a straight road is given by the equation `v=6+8t-t^(2)` where vis in meters per second and t in seconds. The instantaneous acceleration when `t=4.5 s` is :

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The motion of a particle along a straight line is described by equation : x = 8 + 12 t - t^3 where x is in meter and t in second. The retardation of the particle when its velocity becomes zero is.

A car is moving in such a ways that the distance it covers , is given by the equations s = 4t^(2) +3t, where s, is in meters and t is in seconds . What would be the velocity and the accelerations of the car at time t=20 seconds?

The velocity of a particle is given by the equation, v = 2t^(2) + 5 cms^(-1) . Find the instantaneous acceleration at t_(2) = 4s

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?