Home
Class 12
PHYSICS
A pole of length 1.00 m stands half dipp...

A pole of length 1.00 m stands half dipped in a swimming pool with water level 50.0 cm higher than the bed. The refractive index of water is 1.33 and sunlight is coming at an angle of 45° with the vertical. Find the length of the shadow of the pole on the bed.

Promotional Banner

Similar Questions

Explore conceptually related problems

A pole of length 2.00 m stands half dipped in a swimming pool with level 1 m higher than bed (bottom). The refractive index of water is 4//3 and sunlight is coming at an angle of 37^(@) with the vertical. Find the length of the shadow of the pole on the bed. Use sin^(-1)(0.45)=26.8^(@), tan(26.8^(@))=0.5 .

A pole of length 2.00 m stands half dipped in a swimming pool with level 1 m higher than bed (bottom). The refractive index of water is 4//3 and sunlight is coming at an angle of 37^(@) with the vertical. Find the length of the shadow of the pole on the bed. Use sin^(-1)(0.45)=26.8^(@), tan(26.8^(@))=0.5 .

A small piece of wood is floating in the water of depth 1m . The refractive index of water is 4//3 and the sum rays are incident at an angle of 53^(@) to the vertical. Find the location of the shadow of the wood piece on the bottom of the ocean.

If refractive index of glass is 1.50 and of water is 1.33, then criticle angle is

If refractive index of glass is 1.50 and of water is 1.33, then criticle angle is

What is the real depth of a swimming pool when its bottom appears to be raised by 1 m ? Given refractive index of water is 4//3 .

A vertical stick 1.8 m long casts a shadow 45 cm long on the ground. At the same time, what is the length or the shadow of a pole 6 m high?

Find critical angle for glass and water pair, given refractive index of glass is 1.62 and that of water is 1.33.