Let `theta_1` and `theta_2` (where`theta_1 lt theta_2)` are two solutions of `2cot^2theta – 5/(sin theta) + 4 = 0, theta in [0, 2pi)` then `int_(theta_1)^(theta_2) cos^2 3theta d theta` is equal to

int_0^(2pi) theta sin^2 theta cos theta d theta is equal to :

If theta_(1) and theta_(2) be respectively the smallest and the largest values of theta in (0, 2pi)-(pi) which satisfy the equation, 2cot^(2)theta-(5)/(sintheta)+4=0 , then int_(theta_(1))^(theta_(2))cos^(2)3thetad theta is equal to :

If theta_(1) and theta_(2) be respectively the smallest and the largest values of theta in (0, 2pi)-(pi) which satisfy the equation, 2cot^(2)theta-(5)/(sintheta)+4=0 , then int_(theta_(1))^(theta_(2))cos^(2)3thetad theta is equal to :

If 2cos theta+sin theta=1(theta!=(pi)/(2)) then 7cos theta+6sin theta is equal to

If sin theta + 2 cos theta = 1, where 0 lt theta lt (pi)/(2), then what is 2 sin theta - cos theta equal to ?

If cos theta cos 2 theta cos 3theta = 1//4 for 0 lt theta lt pi then theta =

If 0 lt theta lt pi/2 , the solution of the equation sin theta - 3 sin 2 theta + sin 3 theta = cos theta - 3 cos 2 theta + cos 3 theta is