The displacement `x` (in `m`), of a patticle of mass `m` (in `kg`) is related to the time `t` (in second) by `t = sqrt(x) +3`. Find the work done in first six second. (in `mJ`).

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t = sqrt(x) + 3 . The displacement of the particle when its velocity is zero will be.

The displacement x in meters of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in seconds by the equation t=sqrtx+3 , , the work done by the force (in J) in first six seconds is :-

The displacement ‘x’ (in meter)of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t= sqrtx + 3 . The displacement of the particle when its velocity is zero will be:

The displacement x in meter of a particle of mass mkg moving in one dimenstion under the action of a force is related to the time t in second by the equation x=(t-3)^2 . The work done by the force (in joules) in first six seconds is

The displacement x of a body of mass 1 kg on a horizontal smooth surface as a function of time t is given by x = (t^4)/4 . The work done in the first second is

The displacement x of a body of mass 1 kg on a horizontal smooth surface as a function of time t is given by x = (t^4)/4 . The work done in the first second is

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t^2 = sqrt(x) + 2 . The displacement of the particle when its velocity is zero will be.

The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = sqrtx + 3 , where x is in metre and t is in second. The work done by the force in the first 6 second is

Displacement x ( in meters ) , of a body of mass 1 kg as a function of time t, on a horizontal smooth surface , is given as x = 2 t^2 Then work done in the first one second by the external force is