A conducting cel is filled with 0.1 M NaCl solution. Its resistance is found to be 100 `Omega` whereas its conductivity is `10^(-4) Scm^(-1)`. When the same cell is filled with `0.01 M KCl`. Solution, the resistance is found to be `50 Omega`. Calculate molar conductance of 0.01 M KCl solution.

The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .

Resistance of a conductvity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 Omega . The conductivity of this solution is 1.29 Sm^(-1) . Resistance of the same cell when filled with 0.02M of the same solution is 520 Omega . the molar conductivity of 0.02M solution of the electrolyte will be:

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100Omega . The conductivity of this solution is 1.29 S m^(-1) . Resistance of the same cell when filled with 0.2 M of the same solution is 520Omega . The molar conductivity of 0.2 M solution of the electrolyte will be :

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100 Omega. The conductivity of this solution is 1.29S m ^(-1). Resistance of the same cell when filled with 0.2M of the same solution is 520 Omega. The molar conductivity of 0.2M solution of the electrolyte will be

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100Omega . The conductivity of this solution is 1.29 S m^(-1) . Resistance of the same cell when filled with 0.02M of the same solution is 520 Omega . The molar conductivity of 0.02M solution of the electrolyte will be

A conductivity cell filled with 0.01M KCl gives at 25^@C gives the resistance of 604 ohms. The conductivity of KCl at 25^@C is 0.00141Omega^(-1) 1cm^(-1) . The same cell filled with 0.001M AgNO_3 gives a resistance of 6529 ohms. Calculate the molar conductivity of 0.001M AgNO_3 [Conductivity of 0.01M KCl at 25^@C is 0.00141 Omega^(-1) cm^(-1) ]