0.5 N solution of a salt placed between two platinum electrode 2.0cm apart and of area of cross-secton 4.0 sq. cm has a resistance of 25 ohms. Calculate the equivalent conductance of solution.

0.5 N solution of an electrolyte placed between two platinum electrodes 2.0 cm apart and area of cross section 4.0 sq. cm has a resistance of 250 ohm . Calculate the equivalent conductance of the solution.

0.5N solution of a salt placed between two Pt electrodes 2.0 cm apart and having area of cross-section 2.5 cm^(2) has resistance of 25 ohms. Calculate the conductance and cell constant.

1.0 N solution of a salt surrounding two platinum electrodes 2.1 cm apart and 4.2 sq cm in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity of the solution.

1N salt solution surrounding two platinum electrodes, 2.1 cm apart and 6.3 cm^(2) in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductance of the solution.

A 0.05 N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72 cm and having an area of 4.5 cm^(2) has a resistance of 250 ohm. Calculate the equivalent conductance of the solution.

A 0.05N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72cm and having an area of 4.5cm^(2) has a resistance of 250 ohm. Calculate the equivalent conductance of the solution

One normal salt solution surrounding two platinum electrodes, 2.1 cm apart and 6.3 cm^(2) in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity solution.