PC=PR तो सिध्द करो कि `PS gt PQ`

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In the adjoining figure, PQ=PR. Show that PS gt PQ .

In Pr gt PQ and PS bisects /_ QPR . Prove that /_ PSR gt /_ PSQ

In the given figure, Q is a point on the side SR of DeltaPSR such that PQ = PR. Prove that PS gt PQ.

In adjoining figure, seg PR cong seg PQ , show that seg PS gt seg PQ .

If Q is a point on the side SR of a triangle Delta PSR such that PQ = PR then prove that PS > PQ

If Q is a point on the side SR of a triangle PSR such that PQ=PR then prove that PS > PQ

In Fig. 6.3, PS is the bisector of ∠P and PQ = PR . Then ∆PRS and ∆PQS are congruent by the criterion

In the given figure, PS = PR and /_TPS = /_QPR . Prove that PT = PQ .

In triangle PQR PR = Pq , PS bot QR , QT bot PR , RU bot PQ then triangle PQR is symmetrical about