If AB=(3,-2,2), BC=(-1,0 ,-2)sides of a parallelogram, then the obtuse angle between its diagonals is

The vectors AB = 3i - 2j + 2k and BC = - I - 2k are the adjacent sides of a parallelogram. The angle between its diagonals is

A(0,2), B(-2,-1), C(4,0) and D(2,3) are vertices of parallelogram ABCD. If angle between its diagonal is theta then prove that tan theta =3 .

The vector vec(AB)=3hati+2hatj+2hatk and vec(BC)= - hati-2hatk are adjacent sides of a parallelogram ABCD the angle between the diagonals is :

The vector veca=3hati-2hatj+2hatk and vecb=-hati-2hatk are the adjacent sides of a parallelogram. The acute angle between its diagonals is ……….

The vectors AB=3hat i-2hat j+2hat k and vec BC=-hat i+2hat k are the adjacent sides of a parallelogram ABCD then the angle between the diagonals is

Prove that the points (2, - 1), (0, 2), (3, 3) and (5,0) are the vertices of a parallelogram. Also find the angle between its diagonals.

The vectors vec a=3 hat i+2 hat j+2hat k and vec b=-hat i +2hat k are the adjacent sides of a parallelogram. The acute angle between its diagonals is.............

The vectors bar(a)=3bar(i)-2bar(j)+2bar(k) and bar(b)=-bar(i)-2bar(k) are the adjacent sides of a parallelogram. The angle between its diagonals is …………….

If A(3,2,3), B (1,4,6) and C (7,4,5) are the three vertices of a parallelogram ABCD, then the angle between its diagonal through D and the side DC is