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10.78 g of H3 PO4 in 550 ml solution is ...

10.78 g of `H_3 PO_4` in 550 ml solution is 0.40 N. Thus this acid:

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Objective question (single correct answer). i. H_(3) PO_(4) is a tribasic acid and one of its salt is NaH_(2) PO_(4) . What volume of 1M NaOH solution should be added to 12 g of NaH_(2) PO_(4) to convert in into Na_(3) PO_(4) ? a. 100 mL b. 2 mol of Ca (OH)_(2) c. Both d. None iii. The normality of a mixture obtained mixing 100 mL of 0.2 m H_(2) SO_(4) with 100 mL of 0.2 M NaOH is: a. 0.05 N b. 0.1 N c. 0.15 N d. 0.2 N iv 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solutions. The titration was discontinued after adding 30 mL of NaOH solution. The reamining titration was completed by adding 0.25 N KOH solution. The volume of KOH required from completing the titration is: a. 70 mL b. 35 mL c. 32 mL d. 16 mL

Objective question (single correct answer). i. H_(3) PO_(4) is a tribasic acid and one of its salt is NaH_(2) PO_(4) . What volume of 1M NaOH solution should be added to 12 g of NaH_(2) PO_(4) to convert in into Na_(3) PO_(4) ? a. 100 mL b. 2 mol of Ca (OH)_(2) c. Both d. None iii. The normality of a mixture obtained mixing 100 mL of 0.2 m H_(2) SO_(4) with 100 mL of 0.2 M NaOH is: a. 0.05 N b. 0.1 N c. 0.15 N d. 0.2 N iv 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solutions. The titration was discontinued after adding 30 mL of NaOH solution. The reamining titration was completed by adding 0.25 N KOH solution. The volume of KOH required from completing the titration is: a. 70 mL b. 35 mL c. 32 mL d. 16 mL

25 mL of 0.107 M H_(3)PO_(4) was titrated with 0.115 M solution of NaOH to the end point identified by indicator bromocresol green.This required 23.1 mL . The titration was repeated using phenolphthalein as indicator. This time 25 mL of 0.107 M H_(3)PO_(4) reuired 46.2 mL of the 0.115 M NaOH . What is the coefficient of n in this equation for each reaction? H_(3)PO_(4)+n OH^(-)rarr nH_(2)O+[H_(3-n)PO_(4)]^(n-)

0.63 g of diabasic acid was dissolved in water. The volume of the solution was made 100 mL . 20 mL of this acid solution required 10 mL of N//5 NaOH solution. The molecular mass of acid is:

0.63 g of dibasic acid was dissolved in water. The volume of the solution was made 100 mL. 20 mL of this acid solution required 10 mL N/5 NaOH solution. What is the normality of acid.