A sinusoidal voltage `V (t) = 100 sin (500 t)` is applied across a pure inductance of `L = 0.02 H`. The current through the coil is :

A sinusoidal voltage e = 200 sin (100 t) is applied acrossaresistanceof 100Omega then current measured by D.C. ammeter is

A small signal voltage V(t)=V_0 sin omegat is applied across an ideal capacitor C:

Alternating voltage V = 400 sin ( 500 pi t ) is applied across a resistance of 0.2 kOmega . The r.m.s. value of current will be equal to

Alternating voltage V = 400 sin ( 500 pi t ) is applied across a resistance of 0.2 kOmega . The r.m.s. value of current will be equal to